UNIT 3 · PERIODIC MODELING
How do you find amplitude, period and the starting point?
Turn a familiar trigonometric function into a contextual model: identify the extremes, find a complete cycle, then use the starting event to check the phase.

In this guide · 6 sections

A note from your study buddyCheck the starting value and the value half a period later. A familiar equation still needs to fit the situation.
01 / DIRECT ANSWER
Use four quantities to describe one cycle
Amplitude is half the difference between the maximum and minimum outputs; the midline is their average. A period is the time between consecutive matching positions, such as two successive minima. The starting event determines the phase, which you must check by substitution.
For a model written in radians as y = A sin(B(t − C)) + D, the amplitude is |A| and the midline is y = D. For B ≠ 0, the period is T = 2π/|B|. C controls the horizontal shift. Different but equivalent equations can describe the same motion.
Once you can sketch sine and cosine, practice explaining what each number represents, which units it uses and why the starting point makes sense. Aim for a model you can justify rather than a single preferred equation form.
02 / ORIGINAL WORKED EXAMPLE
An observation wheel starting at its lowest point
An observation wheel has a radius of 12 meters, a center 18 meters above the ground and a rotation time of 30 seconds. Let t be the number of seconds since a cabin left the lowest point, and h(t) its height above the ground in meters. Assume constant speed.
- Find the extremes. The minimum height is 18 − 12 = 6 meters; the maximum is 18 + 12 = 30 meters. The amplitude is 12 meters and the midline is 18 meters.
- Translate the period into a coefficient. The motion repeats every 30 seconds, so B = 2π/30 = π/15 radians per second.
- Match the minimum at the start. Since cos(0) = 1, a negative cosine term starts the cabin at its lowest height.
| t (seconds) | h(t) (meters) | Position |
|---|---|---|
| 0 | 6 | Lowest point |
| 7.5 | 18 | Rising through the midline |
| 15 | 30 | Highest point |
| 22.5 | 18 | Falling through the midline |
| 30 | 6 | Back at the lowest point |
Checking h(0) = 6, h(15) = 30 and h(30) = 6 confirms that the model fits these events. Here, 0 ≤ t ≤ 30 describes the first rotation. Extending the model to a longer interval requires the constant-speed assumption to remain reasonable.
03 / COMMON MISTAKES
Three distinctions that matter
A maximum followed by the next minimum spans only half a period. Compare consecutive maxima or consecutive minima to find a complete cycle.
The maximum height includes the height of the center. Amplitude measures the greatest distance from the midline: 12 meters here.
The coefficient π/15 comes from the radian measure 2π. Keep the same angle units when evaluating predictions, and round only at the end.
04 / YOUR TURN
Use a different model to make a prediction
This existing original question uses different parameters and measures time in minutes. Read the units before substituting.
ORIGINAL MCQ · NO ACCOUNT NEEDED
Using , what height is predicted at minutes, to the nearest tenth?
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05 / KEEP GOING
Move from one calculation to an explanation
The practice link opens Original, Unit 3 and topic 3.7. Before each answer, check the starting point, half a period and the units. Then explain what the model’s prediction means in context.
SOURCES & SCOPE
Sources and scope
Course scope was checked against these primary sources on 2026-10-17. Worked examples, explanations and study advice are by AP Exam Kit, which is not affiliated with or endorsed by College Board.
- College Board · AP Precalculus CED (Fall 2026) ↗
Topic 3.7, LO 3.7.A; PDF page 97 / printed page 90. The course scope is official; the observation-wheel example and suggested solution sequence below are original AP Exam Kit teaching content.
AP Exam Kit authored this supplemental guide and checked its cited course sources. Independent teacher review has not been completed; this is not official College Board material.